Ted wants to read the entire Bible as soon as possible in order to teach his next Bible study class. There are 66 books in the Bible from both sections. To do this, Ted can’t read the entire Bible in one sitting, so he decides to divide up the Bible into sections. Then he will read each section a night. Ted’s Bible study class begins in a month. What is the best way to equally divide up the books of the Bible so that Ted will finish in 30 days, but he uses as many days as possible? Use the factors of 66 to find the answer.

Factors of 66 are 1, 2, 3, 6, 11, 22, 33, and 66

Look at the groups below. It shows the different factor groups.

This shows one group of 66 green beans. Both one and 66 are factors of 66. They equally divide into 66 without having remainders.

This picture shows another factor of 66. That is 33. These are 2 groups with 33 toy pieces in each of them. Factors of 66 include 33 and 2.

Three bunches of flowers are shown. Each bunch has 22 flowers in each bunch. Both 3 and 22 are factors of 66.

You see a dice with 6 dots on the dice. There are 11 die. These are like groups, so each group has 6 dots on them. Both 6 and 11 are factors of 66.

So, you know that there are 8 factors for 66. These are 1, 2, 3, 6, 11, 22, 33, and 66. With the books of the Bible, Ted wants to finish reading them in 30 days, so the factor will need to be less than 30. Twenty-two is the closest to 30 without going over. So, there will be 22 days with 3 books of the Bible read during each of the 22 days. However, 22 is a factor of 66 and it needs to be the factor partner of 22. That would be 3.

Challenging Questions

It is the bonus round of a game show, the contestant is having to answer a large number of questions in 10 minutes. Now, there are 66 seconds left of the 10-minute timer. During these 66 seconds, the contestant must answer 3 more questions in order to win the big prize. How many seconds does the contestant have on average to answer those 3 questions? Use the factors of 66 in order to find the answer to this question.

Answer

With 66 seconds left in the bonus round, the contestant would have 22 seconds to spend on each of the 3 questions. The reason is because 3 is a factor of 66. This means that 3 can be divided into 66 without having a remainder. 3’s factor partner is 22 because 3 times 22 is 66.

A crime scene has 66 pieces of evidence tagged. A detective retrieves all 66 pieces of evidence to analyze it to find the criminal. He places them all over his desk. Then he begins to analyze them. When finished, he realizes that the pieces of evidence are categorized into 11 categories. What is the average amount of evidence pieces that could be in each of the 11 categories? Use the factors of 66 in order to find the answer to this question.

Answer

There would be 6 pieces of evidence in each of the 11 categories. This is because 6 and 11 are factors of 66. They are not just factors, but they are factor partners. This means that 6 times 11 equals 66.

A student has only 66 pieces of paper left in her folder to use for classes. She knows she won’t be getting any more, so she must conserve the paper and use it sparingly. There are 11 weeks left of school. If the student allows herself an equal amount of paper for each of the weeks left of the school year, how many pieces will she be allowed to use per week? Use the factors of 66 to find your answer.

Answer

The student would use 6 pieces of paper per week. I don’t know if that is possible, but it could be. The reason is because 6 times 11 equals 66. These are both factors of 66.

Frequently Asked Questions

To factor a number like 66, first know that the number 1 and the number itself, 66, are factors themselves. After that, you must divide each number from 3 to 65 to see if it will divide evenly into 66. You can probably guess that some of the numbers that are close to 66 will not divide into 66 evenly because they are too close to that number. For example, number 65, 64, 63, etc. will not divide evenly into it because they can only divide once into 66. Then they will have a remainder. For 66, 3 can evenly divide into 66 without having a remainder. Its factor partner is 22 because 3 times 22 equals 66. After that, 4, 5, 7, 8, 9 and 10 do not divide evenly into 66 because there would be a remainder for each of those numbers. Once you narrow the factors down to the highest and lowest factor, then you just have to look at those numbers for factors.

There are several factors for 66, and they are 1, 2, 3, 6, 11, 22, 33, and 66.

You may use factoring with the number 66 at any time that there is a math problem with 66. Then the problem would need to have the group of 66 to be divided into groups. When this takes place, then there will the need for factoring. There are not many things that come in groups of 66 because 66 is such a large number. If there are things that come in groups of 66, it is merely by chance.